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Q.

How many moles of $M g_{3} {(P O_{4})}_{2}$ will contain 0.25 mole of oxygen atoms

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a

$1.25 X 10^{- 2}$

b

$3.125 X 10^{- 2}$

c

$2.5 X 10^{- 2}$

d

$1.5 X 10^{- 2}$

answer is C.

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Detailed Solution

1 mole $\begin{array}{l} m g_{3} {(P O_{4})}_{2} = 8 m o l e s o f o x g e n \\ 0.25 m o l e s \\ = \frac{1}{8} X 0.25 \\ = 3.125 X 10^{- 2} m o l e s \end{array}$

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How many moles of Mg3(PO4)2 will contain 0.25 mole of oxygen atoms