Q.

How many moles of sucrose should be dissolved it 500 g of water so as to get a solution which has 3 difference of 104°C between boiling point and freezing point? Kf=1.86K kg mol1,Kb=0.52K kgmol-1)

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a

1.68 

b

 8.40 

c

1.492 

d

0.840 

answer is D.

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Detailed Solution

We know that the boiling point and freezing point of water are 100°C and 0°C respectively, So

1040C=ΔTbΔTf+100C

ΔTbΔTf=4(1.86+0.52)×n500×1000=4n=0.840

= 0.840 moles of sucrose.

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