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Q.

How many moles of ${Na}^{+}$ ions are in 20 mL of 0.4M ${Na}_{3} {PO}_{4} ?$

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a

0.008

b

0.024

c

0.05

d

0.20

answer is B.

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Detailed Solution

${Na}_{3} {PO}_{4} \to 3 {Na}^{+} + {PO}_{4}^{- 3}$

0.4 M 3×0.4 M

= 1.2 M

No. of moles of $N a^{+}$ = ${MV}_{lit}$

$\begin{array}{l} = 1.2 \times \frac{20}{1000} \\ = 0.024 \end{array}$

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How many moles of Na+ ions are in 20 mL of 0.4M Na3PO4?