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Q.

How many non-overlapping triangles can we make in an n-gon (polygon having n sides), by joining the vertices?


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a

n –1    

b

n –2   

c

n –3   

d

n –4 

answer is B.

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Detailed Solution

As we know in a polygon the number of non-overlapping triangles are two less than the number of sides of the polygon.
For example, in a hexagon six sides are there so the number of non-overlapping triangles is n-2=6-2=4 in the hexagon.
So, non-overlapping triangles we can make in an n-gon is n-2.
Hence, option 2 is correct.
 
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How many non-overlapping triangles can we make in an n-gon (polygon having n sides), by joining the vertices?