How many number of moles of sodium hydroxide which would exactly neutralise all the acids produced by complete hydrolysis of one mole of ${\mathrm{SOF}}_4$ ?

$S{O}_{2}C{l}_2+2H_{2}O\to 2HC\mathrm{l}+H_{2}S{O}_4$

To neutralise two moles of $\mathrm{HCl}$and one mole of sulfuric acid, just two moles of sodium hydroxide $\left(\mathrm{NaOH}\right)$ are required.
Four moles of $\mathrm{NaOH}$are required in total to neutralise all of the acids.

$SO{F}_4+H_{2}O⟶H_{2}S{O}_4+4HF$

$H_{2}S{O}_4⟶2$ moles of $\mathrm{NaOH}$

$\mathrm{HF}⟶4$moles of $\mathrm{NaOH}$