How many of the following show (s) disproportionation reaction?(a) XeF4+H2O⟶(b) XeF2+H2O⟶(c) Na2S2O3⋅5H2O⟶Δ(d) P4+NaOH+H2O⟶(e) F2+NaOH⟶(f) Cl2+ cold / dilute NaOH⟶(h) NO2+NaOH⟶[If your answer is 2 then write the answer as 0002.]

Following are the examples of disproportionation reaction,4H3PO3→ heat 3H3PO4+PH3Hg2Cl2→Hg+HgCl22HCO3−→CO32−+H2CO3P4+3NaOH+3H2O→3NaH2PO2+PH3Cl2+H2O→HCl+HClOThere are total 6 such reaction present in the given options.

AI Mentor

Check Your IQ

Free Expert Demo

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

How many of the following show (s) disproportionation reaction?
(a) ${XeF}_{4} + H_{2} O ⟶$
(b) ${XeF}_{2} + H_{2} O ⟶$
(c) ${Na}_{2} S_{2} O_{3} \cdot 5 H_{2} O \overset{Δ}{⟶}$
(d) $P_{4} + NaOH + H_{2} O ⟶$
(e) $F_{2} + NaOH ⟶$
(f) ${Cl}_{2} + cold / dilute NaOH ⟶$
(h) ${NO}_{2} + NaOH ⟶$
[If your answer is 2 then write the answer as 0002.]

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.

An Intiative by Sri Chaitanya

answer is 6.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

Following are the examples of disproportionation reaction,

$\begin{array}{l} 4 H_{3} {PO}_{3} \overset{heat}{\to} 3 H_{3} {PO}_{4} + {PH}_{3} \\ {Hg}_{2} {Cl}_{2} \to Hg + {HgCl}_{2} \\ 2 {HCO}_{3}^{-} \to {CO}_{3}^{2 -} + H_{2} {CO}_{3} \\ P_{4} + 3 NaOH + 3 H_{2} O \to 3 {NaH}_{2} {PO}_{2} + {PH}_{3} \\ {Cl}_{2} + H_{2} O \to HCl + HClO \end{array}$