How many of the following statements are correct?
(I) ‘B’ has a smaller first ionization enthalpy than Be
(II) it is easier to remove 2p electron than 2s electron
(III)2p electron of ‘B’ is more shielded from the nucleus by the inner core of electrons than 2s electrons of Be
(IV) 2s electron has more penetration power than 2p electron
(V) Atomic radius of B is more than Be

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Detailed Solution

$Be \Rightarrow 1 s^{2} 2 s^{2} B \Rightarrow 1 s^{2} 2 s^{2} 2 p^{1}$

Boron has smaller size than Be.

IE of Be is more as it has a fully filled sub shell.

Or we can say the IE of B is less as the outermost electron is more shielded from the nucleus.

In a period left to right atomic radius decreased. It is due to differentiation electron enter into same shell.

2s is more penetrated towards nucleus or more closer to it.

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