How many of the substrates would produce ${\mathrm{H}}_2\mathrm{S}$ when subjected to hydrolysis?

${\mathrm{Cr}}_2{\mathrm{S}}_3,{ \mathrm{Al}}_2{\mathrm{S}}_3, \mathrm{BaS}, {\mathrm{P}}_4{\mathrm{S}}_{10},{ \mathrm{PSCl}}_3,{ \mathrm{Na}}_2\mathrm{S}$

${\mathrm{Cr}}_2{\mathrm{S}}_3 + {\mathrm{H}}_2\mathrm{O} = \mathrm{Cr}{\left(\mathrm{OH}\right)}_3 + {\mathrm{H}}_2\mathrm{S}$

${\mathrm{Al}}_2{\mathrm{S}}_3 + {\mathrm{H}}_2\mathrm{O} = \mathrm{Al}{\left(\mathrm{OH}\right)}_3 + {\mathrm{H}}_2\mathrm{S}$

${\mathrm{P}}_4{\mathrm{S}}_{10} + {\mathrm{H}}_2\mathrm{O} = {\mathrm{H}}_3{\mathrm{PO}}_4 + {\mathrm{H}}_2\mathrm{S}$

${\mathrm{PSCl}}_3+{\mathrm{H}}_2\mathrm{O} = {\mathrm{POCl}}_3+{\mathrm{H}}_2\mathrm{S}$

So, ${\mathrm{Cr}}_2{\mathrm{S}}_3, {\mathrm{Al}}_2{\mathrm{S}}_3, {\mathrm{P}}_4{\mathrm{S}}_{10},{ \mathrm{PSCl}}_3$ are the substrates which produce ${\mathrm{H}}_2\mathrm{S}$ when subjected to hydrolysis.