Q.

How many oxygen atoms will be present in 88 g of CO2 ?

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a

24.09 x 1023

b

22 x 1024

c

44 x 1023

d

6.023 x 1023

answer is A.

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Detailed Solution

1 mole of CO2 = 44 g
88 g of CO2 = 2 moles
No. of oxygen atoms in 2 moles = 2 x 2 x NA
= 2 x 2 x 6.023 x 1023 = 24.09 x 1023

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