How many pairs of positive integers m, n satisfy $\frac{1}{m}+\frac{4}{n}=\frac{1}{12}$ where n is an odd integer less than 60?

 $48m+12n-mn=0\Rightarrow (m-12)(n-48)=576$
 $576=2^6{.3}^2$
No of odd divisors of 576 is 3 (They are 1,3,9)
 $n-48=1or3or9$
 $\Rightarrow n=49,51,57$
Which are all less than 60