How many photons of a radiation of wavelength λ=5×10-7 m must fall per second on a blackened plate in order to produce a force of 6.62×10-5 N ?

F=nhλ⇒n=λFh=5×10-7×6.62×10-56.62×10-34=5×1022

How many photons of a radiation of wavelength λ=5×10-7 m must fall per second on a blackened plate in order to produce a force of 6.62×10-5 N ?

F=nhλ⇒n=λFh=5×10-7×6.62×10-56.62×10-34=5×1022

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How many photons of a radiation of wavelength $λ = 5 \times 10^{- 7} m$ must fall per second on a blackened plate in order to produce a force of $6.62 \times 10^{- 5} N$ ?

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$3 \times 10^{19}$

$5 \times 10^{22}$

$2 \times 10^{22}$

$1.67 \times 10^{18}$

answer is B.

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Detailed Solution

$F = \frac{nh}{λ}$

$\Rightarrow n = \frac{λF}{h} = \frac{5 \times 10^{- 7} \times 6.62 \times 10^{- 5}}{6.62 \times 10^{- 34}} = 5 \times 10^{22}$

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How many photons of a radiation of wavelength λ=5×10-7 m must fall per second on a blackened plate in order to produce a force of 6.62×10-5 N ?

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How many photons of a radiation of wavelength $λ = 5 \times 10^{- 7} m$ must fall per second on a blackened plate in order to produce a force of $6.62 \times 10^{- 5} N$ ?