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How many pieces of plywood, each 0.45 cm thick, are required to make a pile 2.43 m high?

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540

220

234

872

answer is A.

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Detailed Solution

Given,
Thickness of total plywood = 2.43 m and thickness of one plywood = 0.45 cm.
Converting 2.43 m into centimeter.

= 2.43 \times 100

= 243 cm

Thickness of one plywood = 0.45 cm.
Number of pieces of plywood is,

= \frac{Thickness of the pile of plywoods}{Thickness of one piece of plywood}

= \frac{243 \times 100}{0.45 \times 100} = \frac{24300}{45} = 540

The number of pieces of plywood is 540.
Hence option 1 is correct.

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