How many position isomers of n-hexyne are possible?

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answer is C.

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Detailed Solution

$\begin{array}{l} HC \equiv C - {CH}_{2} - {CH}_{2} - {CH}_{2} - {CH}_{3} \\ H_{3} C - C = C - {CH}_{2} - {CH}_{2} - {CH}_{3} \\ H_{3} C - {CH}_{2} - C \equiv C - {CH}_{2} - {CH}_{3} \end{array}$

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