How many protons, neutrons, and electrons are in a silver atom, with a mass number of $108$?

The relation between atomic number, electrons, and protons can be given as:
Atomic number (Z) $=$ No. of electrons $=$ No. of protons

The number of protons and electrons is $47$ because the atomic number (Z) of silver is $47$. 

Atomic mass (A) $=$ Number of protons + Number of neutrons
Number of neutrons $=108-47=61$

 There are $61$ neutrons, and $47$ electrons and protons are present in the silver atom.

Following is a description of the relationship between atomic mass, protons, and neutrons:
Number of protons plus number of neutrons equals atomic mass (A).
Given that silver has an atomic mass of 108.
Additionally, we are aware that there are 47 protons in silver.
Neutron number therefore equals atomic mass (A) - proton number.
Neutron count is 10847=61.
Thus, the silver atom has 61 neutrons along with 47 electrons and protons.

Hence option (A) is correct.