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Q.

How many solutions the following equation has?


3x3=x2+18x+32x2-18x-32-4x2


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a

Four

b

two

c

no solution

d

None 

answer is A.

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Detailed Solution

Given equation is,
3x3=x2+18x+32x2-18x-32-4x2
Solve it as,
3x3=x2+18x+32x2-18x-32-4x2
3x3=x4-(18x+32)2-4x2       [Since (a-b)(a+b)=a2-b2]
3x3=x4-18x2+32+21832x-4x2  [Since a+b2=a2+b2+2ab]
3x3=x4-18x2-32-21832x-4x2  x4-3x3-22x2-21832x-32=0        x4-3x3-22x2-48x-32=0
The highest power of variable in the above equation is 4, so its degree will be 4.
Now the degree of a polynomial is equal to the number of solutions of the polynomial.
Thus, the number of solutions of the equation 3x3=x2+18x+32x2-18x-32-4x2 = 4.
So, the correct option is 1.
 
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