Q.

How many three digit numbers are divisible by 7?


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a

128

b

120

c

121

d

122 

answer is A.

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Detailed Solution

We need to find the number of three digit numbers divisible by 7.
We know the formula,
a n =a+ n1 d   Where,
The first term is a.
The common difference is d.
The number of terms are n.
The list of three-digit numbers divisible by seven is, 105,112,119,...,994
This forms an arithmetic progression of the form a n =a+ n1 d  , where a is the first term, a n   is the n th   term and d is the common difference between the terms.
Thus in the case of the sequence 105,112,119,...,994.
a=105 a n =994 d=7  
Substitute 105 for a , 994 for a n   and 7 for d in the equation a n =a+ n1 d  , 994=105+ n1 7 889= n1 7 n= 889 7 +1 n=128   Thus there are 128 three-digit numbers that are divisible by seven.
Therefore, option 1 is correct.
  
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