How many unpaired electrons are present in $N_{2}^{+}$ ?

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answer is 1.

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Detailed Solution

$\begin{array}{l} N_{2}^{+} (14 - 1 = 13 e^{-}) \\ σ 1 s^{2} \overset{*}{σ} 1 s^{2} σ 2 s^{2} \overset{*}{σ} 2 s^{2} π 2 p_{x}^{2} = π 2 {p_{y}^{2}}^{} 2 {p_{x}}^{1} \end{array}$

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