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Q.

How many unpaired electrons will be there in the valence shell of the iron atom in the complex $[Fe {(CN)}_{2} {({OH}_{2})}_{4}] {NO}_{3} ?$

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a

$4$

b

$5$

c

$3$

d

$2$

answer is D.

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Detailed Solution

$[Fe {(CN)}_{2} {({OH}_{2})}_{4}] {NO}_{3}$

Question Image

No. of unpaired electrons = $5$

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