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Q.

How much energy is required to separate the typical middle mass nucleus 50120Sn into its constituent nucleons. (Mass of 50120Sn=119.902199 u ; mass of proton =1.007825 u and mass of neutron=1.008665 u )

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a

921 Mev

b

1021 Mev

c

821 Mev

d

1121 Mev

answer is A.

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Detailed Solution

50Sn120;  Z=50,  A−z=70

Δm=zmp+(A−z)mn−M

=50×1.007825+70×1.008665−119.902199 =50.39125+70.60655−119.902199

=1.095601 amu

BE=Δm×931.5Mev=1.095601×931.5 Mev

        =1021Mev

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