How much amount of CaCO3 in gram having percentage purity 50 percent produces 0.56 litre of CO2 at STP on heating?

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How much amount of $C a C O_{3}$ in gram having percentage purity 50 percent produces 0.56 litre of $C O_{2}$ at STP on heating?

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answer is 5.

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Detailed Solution

$C a C O_{3} \to C a O + C O_{2}$

$0.56 l i t r e = \frac{1}{40} m o l e$

Amount of pure $C a C O_{3}$ required $= \frac{1}{40} \times 100 = \frac{5}{2} g$
Percentage purity is =50%
So, amount required = 5 g

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