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Q.

How much energy is released when 6 mole of octane is burnt in air? Given ∆Hf0 for CO2(g), H2O(g) and C8H18(l) respectively are -390,-240 and +160KJ/mol

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a

-37.4MJ

b

-35.5MJ

c

-20.0MJ

d

-32.6MJ

answer is A.

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Detailed Solution

6C8H18+75O2→48CO2(g)+54H2O(g)

6C8H18=6(160)=960

48CO2=48(-390)=-18720

54H2O=54-240=-12960

=-18720-12960-960=-32640kj/mol

=-32.64MJ

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