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Q.

How much energy must a gamma ray photon have, if it is to materialize into a pair of electron and positron with each particle having a K.E. of 1 MeV?

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a

3.02 MeV

b

1.0 MeV

c

2 MeV

d

0.51 MeV

answer is B.

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Detailed Solution

Eγ = (rest mass energy of e-) + (rest mass energy of e+) + KEpair 
= 0.51+ 0.51+ 2 = 3.02Mev

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