How much force will a cylindrical object of length 49 cm, radius 7 cm, and density 2.2 g/cm³ exert on a table? (Consider g = 10 m/s²)

The radius of the base (r)=7 cm
Length of the cylinder (l)=49 cm
Density(d)=2.2 g/cm³
Acceleration due to gravity (g)=10 m/s²

To find the gravitational force, first, we will have to calculate the mass of the cylinder.
Mass of the cylinder = Volume(V)× density (d) = πr²l × d

(∴ Volume of the cylinder =πr²l)

Mass of the cylinder =$\frac{22}{7} \times 7\times 7 \times 49 \times 2.2=16601.2$ g

Mass of the cylinder = 16.601 kg ($\because 1 \mathrm{kg} = 1000 \mathrm{g}$)

Gravitation Force  = mass x acceleration due to gravity (g) 

$\Rightarrow$F = 16.601×10=166.01N

Therefore, the cylinder will exert around 166 N force on the table.