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How much heat energy in joules must be supplied to 14 gms of nitrogen at room temperature to raise its temperature by $40 ° C$ at constant pressure? (Mol. wt. of $N_{2} = 28$ gm, R = universal gas constant)

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80 R

70 R

60 R

50 R

answer is C.

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Detailed Solution

${(ΔQ)}_{p} = {nC}_{p} ΔT = \frac{14}{28} \times \frac{7}{2} R \times 40 = 70 R$

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