How much mass of sodium acetate is required to make 250 mL of 0.575 molar aqueous solution?

Molar mass of sodium acetate (CH₃COONa)
= 82 g mol^-
Mass of CH₃COONa required to make 250 mL of 0.575 M
solution $=\frac{0.575\times 82\times 250}{1000}=11.79 \mathrm{g}$