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How much mercury must be placed inside a glass flask having an internal volume of 300c.c so that the volume of the remaining space inside the flask may be constant at all temperatures?( $γ,$ of mercury = $0.00018 /^{0} C, a_{g} = 0.00001 /^{0} C)$

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40 c.c

30 c.c

10 c.c

50 c.c

answer is D.

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Detailed Solution

$V_{1} r_{1} = V_{2} r_{2} \Rightarrow V_{1} = \frac{V_{2} \times 3 α_{2}}{r_{1}} = \frac{300 \times 3 \times 0.00001}{0.00018} = 50 c . c .$

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