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Q.

How much solid oxalic acid (Molecular weight 126) has to be weight to prepare 100 mL exactly 0.1 (N) oxalic solution in water?

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a

0.063 g

b

1.26 g

c

0.126 g

d

0.63 g

answer is C.

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Detailed Solution

Given: Molecular weight = 126g/mol

‘n’ factor = 2

eq.w.t=1262=63g/mol.

M=W×1000molecular  weight×Vol

0.1=W×100063×100

W=0.63 g

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