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Q.

How much steam at 100°C is to be passed into water of mass 100g at 20°C to raise its temperature by 5°C ? (Latent heat of steam is 540cal/g and specific heat of water is 1 cal/g°C )

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a

5.9gm

b

9.16gm

c

2.91gm

d

0.813gm

answer is A.

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Detailed Solution

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Heat lost by steam = Heat gained by water
⇒MsLs+MsSωth−tR=MsSωtR−tC⇒Ms×540+Ms×1(100−25)=100×1(25−20)⇒Ms=0.813gm

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