How much steam at 100°C is to be passed into water of mass 100g at 20°C to raise its temperature by 5°C ? (Latent heat of steam is 540cal/g and specific heat of water is 1 cal/g°C )

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5.9gm

9.16gm

2.91gm

0.813gm

answer is A.

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Detailed Solution

Heat lost by steam = Heat gained by water
$\begin{array}{l} \Rightarrow M_{s} L_{s} + M_{s} S_{ω} (t_{h} - t_{R}) = M_{s} S_{ω} (t_{R} - t_{C}) \\ \Rightarrow M_{s} \times 540 + M_{s} \times 1 (100 - 25) = 100 \times 1 (25 - 20) \\ \Rightarrow M_{s} = 0 .813 gm \end{array}$

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