How much sulphur is to be burnt to produce $0.224$ lit of ${\mathrm{SO}}_2$ at NTP?

The balanced equation for ${\mathrm{SO}}_2$ formation is

$\mathrm{S}+{\mathrm{O}}_2⟶{\mathrm{SO}}_2$

From the above equation it is considered that $32 \mathrm{g}$ of sulphur produces $22.4 \mathrm{L}$ of ${\mathrm{SO}}_2$. Then for the production of $0.224$ lit of ${\mathrm{SO}}_2$ at NTP it requires $32/22.4\times 0.224=0.32 \mathrm{g}$