Q.

How much will be the change in reduction potential of hydrogen electrode when its solution initially at pH = 0 is neutralised to pH = 7 ?

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a

increase by 0.059 v

b

decrease by 0.059 v

c

decrease by 0.41 v  

d

increase by 0.41 v

answer is C.

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Detailed Solution

E0=E+0.05911log107=E0+0.0591x(7)=E0041v (or) E=0.0591×pH

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How much will be the change in reduction potential of hydrogen electrode when its solution initially at pH = 0 is neutralised to pH = 7 ?