How much work should be done on a bicycle of mass 20kg to increase its speed from 2ms^-1 to 5ms^-1?

Given data:
Mass of bicycle, m = 20 kg
The initial speed of the bicycle, u = 2 ms^-1
The final speed of the bicycle, v = 5 ms^-1
To find the work done:
We know that whenever work is done, an equal amount of energy is used up.
According to the work-energy theorem, the work done in this case will be equal to the change in kinetic energy of the bicycle when its speed changes from 2ms^-1 to 5ms^-1.
Mathematically express:

Work done = Final K.E - Initial K.E
$\Rightarrow$             $=\frac{1}{2}{\mathrm{mv}}^2-\frac{1}{2}{\mathrm{mu}}^2$
$\Rightarrow$             $=\frac{1}{2}\times 20\times 5^2-\frac{1}{2}\times 20\times 2^2$
$\Rightarrow$              = 250 - 40
$\Rightarrow$              = 210 J
Hence, the work done is 210 J.
The work done should be 210 J to increase the speed from 2ms^-1 to 5ms^-1.