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How much would a $W_{e} kg - wt$ man weigh on the moon in terms of gravitational units?

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\frac{W_{e}}{6} kg - wt

6 W_{e} kg - wt

W_{e} kg - wt

Zero

answer is A.

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Detailed Solution

A person weighing

W kg - wt

on Earth will weigh

\frac{W}{6} kg - wt

on the moon
We know that the body’s weight is given by

W_{e} = mg

. So,

W_{e} = mg

. The acceleration due to gravity on the surface of the moon is

\frac{1}{6}

that of the Earth. Hence,

W_{m} = m \times \frac{g}{6}

\Rightarrow

W_{m} = \frac{W_{e}}{6}

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