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Human body requires 2370 K. Cal of energy daily. The heat of combustion of glucose is –790 K.cal/mole. The amount of glucose required for daily consumption is

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650g

540g

327g

490.5g

answer is B.

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Detailed Solution

\large {C_6}{H_{12}}{O_{{6_{(g)}}}}\; + \;6{O_{{2_{(g)}}}}\; \to \;6{CO_{{2_{(g)}}}}\; + \;6{H_2}{O_{(l)}}

GMW of glucose= 180 g;

Weight of glucose required= $\frac{2370 \times 180}{790} = 540 grams;$

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