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Q.

Human body requires 2370 K. Cal of energy daily. The heat of combustion of glucose is –790 K.cal/mole. The amount of glucose required for daily consumption is

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a

650g

b

540g

c

327g

d

490.5g

answer is B.

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Detailed Solution

\large {C_6}{H_{12}}{O_{{6_{(g)}}}}\; + \;6{O_{{2_{(g)}}}}\; \to \;6{CO_{{2_{(g)}}}}\; + \;6{H_2}{O_{(l)}}

 

  

\large {\Delta _{com}}H = - 790K.cal


 

 GMW of glucose= 180 g;

Weight of glucose required= 2370×180790=540 grams ;

                                                                    

 


 

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