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Q.

Hybridization of Al in AlCl₃ and in ${AlCl}_{4}^{-}$ is respectively

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a

sp³,sp²

b

sp³,sp³

c

sp²,sp²

d

sp²,sp³

answer is D.

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Detailed Solution

AlCl₃ has 3 sigma bonds = sp²

${AlCl}_{4}^{-}$ has four sigma bonds = sp³

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