Hybridization of central atom in ${NO}_{2}^{-}, {NH}_{2}^{-}, {NO}_{2}^{+}$ respectively

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$sp, {sp}^{2}, {sp}^{3}$

${sp}^{2}, {sp}^{3}, sp$

${sp}^{2}, {sp}^{3}, {sp}^{2}$

$sp, {sp}^{3}, {sp}^{2}$

answer is B.

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Detailed Solution

$\begin{array}{l} {NO}_{2}^{-} . ... 2 bp + 1 lp . .... {sp}^{2} \\ {NH}_{2}^{-} . ... 2 bp + 2 lp . .... {sp}^{3} \\ {NO}_{2}^{+} . ..... 2 bp + zero lp .... sp \end{array}$

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