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Q.

Hybridization of central atom in SiCl4 is

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a

sp2

b

sp3

c

sp

d

sp3d

answer is C.

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Detailed Solution

Number of electron pairs(EP)=V+M-C+A2; V=Group number of central atom; M=-H, -X, -OH....monovalent groups attached to central atom ; C=Charge of cation ; A=Charge of anion ; V=2,3,4,5,6,7,8 respectively for 2nd , 13th, 14th,15th, 16th,  17th, 18th group elements ; Number bond pairs, BP(according to VSEPR theory)=Number of atoms directly attached to central atom;                                                                            =4,3,2 respectively in CH4(CX4), NH3 , H2O ; Number lone pairs on central atom(LP)=EP-BP ;                                                          =0,1,2 respectively in  CH4(CX4), NH3 , H2O ; CH4(CX4)-'4' bp +'0' lp  on central atom ; sp3-Tetrahedral ; NH3(NX3)....PX3,AsX3,SbX3,BiX3,-'3' bp +'1' lp  on central atom ; sp3-Pyramidal ; H2O(OF2, X2O)...SX2,SeX2,TeX2-'2' bp +'2' lp  on central atom ; sp3-Bent or angular or V-shape ; Note; Each bonded halogen atom has '3' lone pairs on it ; RX4---12  lone pairs/molecule----R--14th group element ; RX3---10 lone pairs/molecule----R--15th group element ; RX2---8 lone pairs/molecule------R--16th group element ;  XO----6  lone pairs/ion------    X--17th group element ;         Orientation of all electron pairs is tetrahedral ; Bond angle-CH4(109°) , NH3(107°) , H2O(105°) , Cl2O(111°) , OF2(102°) , SCl2(102°), NF3(102°) ; *****XO- has 1 bp +3 lp on central atom-sp3-linear ; 

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