Hybridization of sulphur atom in all oxo acids of sulphur is

In all oxo acids of sulphur the hybridization of central atom is ${\mathrm{sp}}^3$

It can be in 1st excited state (or) 2nd excited state

S(Z=16) :  I excited state configuration is

Represents tetravalency;

Sulphur forms 3 $\mathrm{\sigma }$ bonds and one $\mathrm{d\pi }-\mathrm{p\pi }$ bond with oxygen atom;

There is  a lone pair on Sulphur atom;

S(Z=16) : II excited state configuration is…$\left[\mathrm{Ne}\right]3{\mathrm{s}}^{1}3{\mathrm{p}}^{3}3{\mathrm{d}}^2$;

Hybridization is ${\mathrm{sp}}^3;$

Represents hexavalency;

Sulphur forms four $\mathrm{\sigma }$ bonds  and  two $\mathrm{d\pi }-\mathrm{p\pi }$ bonds with oxygen atoms