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Q.

Hybridization, shape, and magnetic moment of K3CoCO33 are:

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a

dsp2, square planar, 4.9B.M

b

sp3, tetrahedral, 4.9 B.M. 

c

d2sp3, octahedral4.9 B.M

d

sp3d2, octahedral, 4.9 B.M. 

answer is B.

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Detailed Solution

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K3​[Co(CO3​)3​]
     +3              d6 configuration
weak ligand so no pairing and high spin complex forms
so sp3d2 hybridization takes place and octahedral complex forms
Also as it have 4 unpaired electron so 
magnetic moment
μ=n(n+2)​=4.9 BM
n = no of unpaired electron

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