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Q.

Hydration energies of ${Li}^{+}$ and ${Cl}^{-}$ are - 499 and -382 k.J ${mole}^{- 1}$ . If lattice energy of LiCl is +840 k.J ${mole}^{- 1}$ , heat of solution of $LiCl$ is

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a

+41 kJ ${mole}^{- 1}$

b

-12.22 kJ mole^-1

c

– 1621 kJ ${mole}^{- 1}$

d

– 41 kJ ${mole}^{- 1}$

answer is D.

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Detailed Solution

$\begin{array}{l} {ΔH}_{LiCl}^{Sol} = {ΔH}_{LiCl}^{Hydration} + Latticeenergy \\ = - 499 + (- 382) + 840 \\ = - 41 kJ / mol \end{array}$

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