Hydride of boron occurs as B2H6 but B2Cl6 does not exist. This is because

pπ - dπ back bonding is possible in B 2 H 6 but not in B 2 Cl 6

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Hydride of boron occurs as B₂H₆ but B₂Cl₆ does not exist. This is because

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Boron and chlorine have almost equal atomic sizes

$pπ - dπ$ back bonding is possible in B₂H₆ but not in B₂Cl₆

Small hydrogen atoms can easily fit in between boron atoms but large chlorine atoms do not

Boton and hydrogen have almost equal values of electronegativity

answer is D.

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Detailed Solution

Hydride of boron occurs as B₂H₆ but B₂Cl₆ does not exist. This is because small hydrogen atoms can easily fit in between boron atoms but large chlorine atoms do not.
Note: Instead of B₂Cl₆, the stable compound is BCl₃ which acts as a Lewis acid and accepts a lone pair of electrons from ammonia to form BCl₃←NH₃.

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