Hydroboration-oxidation of ${CH}_{3} CH = {CH}_{2}$ produces

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${CH}_{3} {CH}_{2} {CH}_{2} OH$

${CH}_{3} CH (OH) {CH}_{3}$

${CH}_{3} CH (OH) {CH}_{2} OH$

${CH}_{3} {COCH}_{3}$

answer is A.

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Detailed Solution

An alkene is transformed into a neutral alcohol in a two-step organic process called a hydroboration-oxidation reaction by the net addition of water across the double bond. The Anti-Markownikoff principle is followed.

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