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Hydrocarbons B and C are

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Both B and C are alkenes

Both B and C are alkynes

B is an alkyne whereas C is an alkene

B is an alkene whereas C is an alkyne

answer is C.

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Detailed Solution

$A = {CH}_{2} Br - {CH}_{2} Br \to_{- 2 HBr}^{{NaNH}_{2}} CH \equiv CH (B)$

$- {ZnBr}_{2} ↓ Zn / C_{2} H_{5} OH$

${CH}_{2} = {CH}_{2} (C)$

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