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Hydrochloric acid solutions A and B have concentration of 0.5 N and 0.1 N respectively. The volume of solutions A and B required to make 2 litres of 0.2 N hydrochloric are

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0.5 L of A + 1.5 L of B

1.5 L of A + 0.5 L of B

1.0 L of A + 1.0 L of B

0.75 L of A + 1.25 L of B

answer is A.

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Detailed Solution

$NV = N_{1} V_{1} + N_{2} V_{2}$

$\begin{array}{l} 0 .2 \times 2 = 0 .5 x + 0 .1 (2 - x) \\ 0 .4 = 0 .5 x + 0 .2 - 0 .1 x \\ 0 .2 = 0 .4 x \\ x = V_{1} = \frac{1}{2} L = 0 .5 L; V_{2} = 2 - 0.5 = 1.5 L \end{array}$

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