Hydrogen atom in ground state is excited by a monochromatic radiation of λ = 975A0. Number of spectral lines in the resulting spectrum emitted will be

1λ=RZ21n12−1n221975×10−10=1.097×107112−1n2;n=4no of spectral lines n(n−1)2=4(4−1)2=6

Hydrogen atom in ground state is excited by a monochromatic radiation of λ = 975A0. Number of spectral lines in the resulting spectrum emitted will be

1λ=RZ21n12−1n221975×10−10=1.097×107112−1n2;n=4no of spectral lines n(n−1)2=4(4−1)2=6

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Hydrogen atom in ground state is excited by a monochromatic radiation of $λ$ = 975A⁰. Number of spectral lines in the resulting spectrum emitted will be

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Detailed Solution

$\begin{array}{l} \frac{1}{λ} = {RZ}^{2} [\frac{1}{n_{1}^{2}} - \frac{1}{n_{2}^{2}}] \\ \frac{1}{975 \times 10^{- 10}} = 1 .097 \times 10^{7} [\frac{1}{1^{2}} - \frac{1}{n^{2}}]; n = 4 \end{array}$
no of spectral lines $\frac{n (n - 1)}{2} = \frac{4 (4 - 1)}{2} = 6$