Q.

Hydrogen bonds are formed in many compounds e.g., H2OHFNH3 . The boiling point of such compounds depends to a large extent on the strength of hydrogen bond and the number of hydrogen bonds. The correct decreasing order of the boiling points of above compounds is :

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a

NH3>H2O>HF

b

HF>H2O>NH3

c

NH3>HF>H2O

d

H2O>HF>NH3

answer is B.

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Detailed Solution

The size and electronegativity of the atom affect how strongly hydrogen bonds with other molecules.
A smaller atom has a higher electronegativity, which makes its H-bonding stronger. As a result, H...F>H...O>H...N is the order of H-bonding strength.
However, each HF molecule is only joined to two other HF molecules, whereas each H2O  molecule forms an H-bond with four more H2Omolecules.
H2O>HF>NH3 is the order of decreasing boiling points as a result.

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Hydrogen bonds are formed in many compounds e.g., H2O, HF, NH3 . The boiling point of such compounds depends to a large extent on the strength of hydrogen bond and the number of hydrogen bonds. The correct decreasing order of the boiling points of above compounds is :