Hydrogen peroxide can act like an acid, oxidant, reductant, bleaching agent, antichlor and an antiseptic. The reaction from the following in which it acts like a reducing agent is

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$PbS$ + $4 H_{2} O_{2} \overset{}{\to} {PbSO}_{4} + 4 H_{2} O$

${Mn}^{+ 2} + 2 H^{+} + H_{2} O_{2} \overset{}{\to} {Mn}^{+ 4} + 2 H_{2} O$

$2 {MnO}_{4}^{-} + 5 H_{2} O_{2} + 6 H^{+} \overset{}{\to} 2 {Mn}^{+ 2} + 8 H_{2} O + 5 O_{2}$

$H_{2} O_{2} + 2 H^{+} + 2 I^{-} \overset{}{\to} I_{2} + 2 H_{2} O$

answer is C.

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Detailed Solution

(1) $\overset{}{Pb \overset{- 2}{S}} \overset{}{\to} \overset{+ 6}{{PbSO}_{4}} . . . . . oxidation$

(2) ${Mn}^{+ 2} \overset{}{\to} {Mn}^{+ 4} . . . . . oxidation$

(3) $\overset{+ 7}{M} n O_{4}^{-} \overset{}{\to} {Mn}^{+ 2} . . . . . redution$

(4) $I^{-} \overset{}{\to} I_{2} . . . . . oxidation$

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