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Hydrogen peroxide in aqueous solution decomposes on warming to give oxygen according to the equation
$2 H_{2} O_{2} (a q) ⟶ 2 H_{2} O (l) + O_{2} (g)$
$24 {dm}^{3} \cdot 100 {cm}^{3}$ of X M solution of $H_{2} O_{2}$ produces $3 {dm}^{3}$ of $O_{2}$ • Thus, X is :

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2.5

0.5

0.25

answer is A.

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Detailed Solution

Here,

$24 {dm}^{3} \to 1 mole of O_{2} gas.$

$3 {dm}^{3} \to \frac{3}{24} = \frac{1}{8} mole of O_{2} gas$

$2 H_{2} O_{2} \to 2 H_{2} O + O_{2}$

$n_{H_{2} O_{2}} = 2 \times n_{O_{2}} = 2 \times \frac{1}{8} = \frac{1}{4} moles$

$∴ X \times 0 .1 = 0 .25 \Rightarrow X = 2 .5$

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