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Q.

Hydrolysis constant of salt derived from strong acid and weak base is $2 \times 10^{- 5}$ . The dissociation constant of the weak base is

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a

$5 \times 10^{- 8}$

b

$2 \times 10^{- 19}$

c

$5 \times 10^{- 9}$

d

$5 \times 10^{- 10}$

answer is C.

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Detailed Solution

$K_{h} = \frac{K_{w}}{K_{b}}$

$2 \times 10^{- 5}$ = $\frac{1 \times 10^{- 14}}{K_{b}}$

$K_{b}$ = $\frac{1 \times 10^{- 14}}{2 \times 10^{- 5}}$

$K_{b}$ = $5 \times 10^{- 10}$

Hence, the correct option is option (C) $5 \times 10^{- 10}$ .

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