Hydrolysis of ${\mathrm{XeF}}_2$ gives

One molecule of ${\mathrm{XeF}}_2$ upon reaction with one molecule of water  produces stable $\mathrm{Xe}$ atom, one molecule of hydrogen flouride and half molecule of oxygen. The reaction is as follows

 ${\mathrm{XeF}}_2+{\mathrm{H}}_2\mathrm{O}\to \mathrm{Xe}+2\mathrm{HF}+1/2{\mathrm{O}}_2$

From the above reaction it is concluded that ${\mathrm{XeF}}_2$ upon hydrolysis  gives

$\mathrm{Xe}$, $\mathrm{HF}$ and ${\mathrm{O}}_2$ products.