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I g of $H_{2} O$ changes from liquid to vapour phase at constant pressure at I atm. The pressure increases from 1 cc to l67l cc. The heat of vaporization at this pressure is 540 cal/g. The increase in internal energy of water is

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3000 J

992 J

2122 J

2099 J

answer is A.

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Detailed Solution

W = $P (dV) = 0.01 \times 10^{5} (1671 - 1) \times 10^{- 6} = 167 J$

$Q = ∆ U + W$

or $∆ U = Q - W = mL - 167 = 540 \times 4.2 = 167$

= 2099 J

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